A small covers a distance $100$ metre in $50$ hours. Calculate the average speed of snail in $k m / h$

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Solution

$\begin{matrix} D i s tan c e c o v r e d b y s m a l l = 100 m i n 50 h o u r s t h e n, \Rightarrow a v e r a g e s p e e d = \frac{100 m}{50 h o u r} = \frac{\frac{100}{1000} k m}{50 h o u r} \Rightarrow \frac{\frac{1}{10} k m}{50 h o u r} = \frac{1 k m}{500 h} \Rightarrow 0.002 k m / h \end{matrix}$

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