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Question

A small cube with mass M starts at rest point 1 at a height 4R, where R is the radius of the circular part of the track. The cube slides down the frictionless track and around the loop. The force that the track exerts on the cube at point 2 is nearly __________ times the cube's weight Mg.
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A
1
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B
2
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C
3
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D
4
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Solution

The correct option is C 3
Velocity at bottom most point=8gr
Now, at 2 its displacement from bottom most point is 2R,
The velocity at 2 will be:
v2=u2+2asv2=8gR+2(g)(2R)v2=4gRNow,netforceat2=F+mg=mv2RF=m(4gR)Rmgf=3mg
Hence,
option (C) is correct answer.

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