A small hole of area of cross-section 2mm2 is present near the bottom of a fully filled open tank of height 2 m. Taking g=10m/s2 , the rate of flow of water through the open hole would be nearly
A
12.6×10–6m3/s
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B
8.9×10–6m3/s
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C
2.23×10–6m3/s
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D
6.4×10–6m3/s
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Solution
The correct option is A12.6×10–6m3/s Velocity of efflux, v=√2gh
Volume flow rate, Q=Av=A√2gh=(2×10−6)(2×10×2)1/2=4√10×10−6m3/s≈12.6×10−6m3/s