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Question

A small hot surface at temp 425 K having an emissivity of 0.85 dissipates heat by radiation into a surrounding area at 400 K. The equivalent radiation heat transfer coefficient in W/m2K is

A
13.5
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B
6
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C
11
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D
8
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Solution

The correct option is A 13.5
Rediative heat transfer=εσA(T41T42)

=hrA(T1T2)

εσ(T21+T22)(T1+T2)(T1T2)=hr(T1T2)

hr=εσ(T21+T22)(T1+T2)

=0.85×5.67×108(4252+4002)(425+400)

hr=13.54W/m2K

hr=radiative heat transfer corfficient.

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