A piece of ice of mass 40 g is dropped into 200 g of water at 50 $^{\circ} C$ . Calculate the final temperature of the water after all the ice has melted. (Specific heat capacity of water = 4200 J/kg $^{\circ} C$ , specific latent heat of fusion of ice $= 336 \times 10^{3}$ J/kg)

Join BYJU'S Learning Program

A small quantity, mass m, of water at a temperature θ(in∘C) is poured on to a large mass M of ice which is at its melting point. If c is specific heat capacity of water and L the latent heat of fusion of ice, then the mass of ice melted is given by

The correct option is C mcθL.Heat gain is mc(θ−0)Heat loss if ice is m1L;m1 is ice melted.m1L=mcθ⇒m1=mcθ/L

A small quantity, mass $m$ , of water at a temperature $θ (i n^{\circ} C)$ is poured on to a large mass $M$ of ice which is at its melting point. If $c$ is specific heat capacity of water and $L$ the latent heat of fusion of ice, then the mass of ice melted is given by

The correct option is C $\frac{m c θ}{L}$ .
Heat gain is $m c (θ - 0)$
Heat loss if ice is $m_{1} L; m_{1}$ is ice melted.
$m_{1} L = m c θ$
$\Rightarrow m_{1} = m c θ / L$