The activity varies according to the equation,
A(t)=A0 e−λt
or, A(t)=A0(12)t/T1/2
In the problem, A (t=5hr)=296 disintegrations/min,
29660=A0 (12)5/15
or, A0=29660×21/3=6.22 disintegrations/sec.
= the initial activity of 1 cc. of blood.
If the total volume of blood is V cc.,
6.22 V=3.7 ×1010×10−6⇒V=5.9 ℓ.