We have,
The snail covers 1 cm. in the first hour, 12 cm.in the next hour 14 cm in the next hour and so on.
Then G.P.
1,12,14.......
This G.P.
$\begin{align}
a=1
d=12
Now,
So,
Sn=3
⇒a(1−rn)1−r=3
⇒1[1−(12)n]1−12=3
⇒1−(12)n=32
⇒(12)n=−12
Now, there is no
value of n such that above equation.