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Question

A small solid cylinder of radius r and mass M slides down a smooth hill of height h from rest and gets onto the plank of mass M lying on the smooth horizontal plane at the base of the hill as shown in the figure. Due to friction between the cylinder and plank, the cylinder slows down and starts rolling without friction over the plank. While the cylinder is rolling (without sliding) over the plank, the velocity of the plank is vp, the velocity of centre of mass of the cylinder is vc and angular velocity of the cylinder is “ω”. The coefficient of friction between the cylinder and plank is μ , while gravity (g) is uniform in the space.
[Assume that height of the plank is negligible.]

The fraction of initial mechanical energy that is lost due to friction is

A
14
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B
116
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C
38
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D
12
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Solution

The correct option is C 38
Wfr=μMg×L=38Mgh
or Wfrtotal mechanical energy=38

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