The correct option is
D n2>n3>n1
Let
n1,
n2 and
n3 be the frequencies heard when the source is at
A,
B and
Crespectively and an observer is standing on
O.
From Doppler effect the apparent frequency heard by the observer,
n1=n(v+v0v∓vs)
n= actual frequency of the sound,
v= speed of sound in medium,
v0= speed of observer,
vs= speed of source,
At point
A, source is moving away from observer, so the apparent frequency
n1=n(vv+vs)
which is less than actual frequency
(n).
n1<n
At point
B, source is moving towards the observer, so the apparent frequency
n2=n(vv−vs)
which is more than actual frequency
(n).
n2>n
At point
C, source is moving perpendicular to the observer, so the apparent frequency is little higher than actual frequency but less than point
B.
n3=n
Therefore, the combined result of these three statements are expressed as,
n2>n3>n1
Final answer: (b)