A small sphere falls from rest in a viscous liquid. Due to friction heat is produced. If 'Q' is the rate of production of heart at the terminal speed and r is the radius of the sphere, the 'Q' is proportional to

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
$f = 6 π n r v$ but $v α r^{2} f α r^{3}$
$Q = f . v$ $Q α r^{5}$

Suggest Corrections

Similar questions

A small sphere of radius r falls from rest in a viscous liquid. As a result, heat is produced due to viscous force. The rate of production of heat when the sphere attains its terminal velocity is proportional to:

Q. A small sphere of radius

r

falls from rest in a viscous liquid. Heat is produced due to friction between the liquid and the sphere. Choose the correct relation between rate of production of heat and the radius of the sphere, when terminal velocity is attained.

Q. A small sphere initially at rest, falls in to a viscous liquid. Due to drag, heat is produced. Then the relation between rate of production of heat and the radius of the sphere at terminal velocity, is best represented by:

Q. A small sphere falls from rest in a liquid. Due to viscosity heat is produced. Find the relation between the rate of production of heat and the radius of the sphere at terminal velocity.

Q. A small spherical drop fall from rest in viscous liquid. Due to friction, heat is produced. The correct relation between the rate of production of heat and the radius of the spherical drop at terminal velocity will be

Join BYJU'S Learning Program

A small sphere falls from rest in a viscous liquid. Due to friction heat is produced. If 'Q' is the rate of production of heart at the terminal speed and r is the radius of the sphere, the 'Q' is proportional to

The correct option is D f=6πnrv but vαr2fαr3 Q=f.v Qαr5

The correct option is D
$f = 6 π n r v$ but $v α r^{2} f α r^{3}$
$Q = f . v$ $Q α r^{5}$