A small sphere of mass 1kg is moving with a velocity 6- - - ms-1 - It hits a fixed smooth wall and rebound with velocity 4- - - ms-1 - The coefficient of restitution between the sphere and the wall is-

The correct option is A 2/3Impulse = Change in momentum nbsp; 1(4î + ĵ) 1(6î _+ĵ) = 2î Which is perpendicular to the wall.Component of initial velocity ...

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Standard XII

Physics

The 'e' Equation

A small spher...

Question

A small sphere of mass 1kg is moving with a velocity $(6^i +^j) {ms}^{- 1}$ . It hits a fixed smooth wall and rebound with velocity $(4^i +^j) {ms}^{- 1}$ . The coefficient of restitution between the sphere and the wall is.

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Solution

The correct option is A 2/3
Impulse = Change in momentum $1 (4^i +^j) - 1 (6 {^i}_{+}^j) = - 2^i$

Which is perpendicular to the wall.

Component of initial velocity along $^i = 6^i$

$\Rightarrow$ Speed of approach = 6 m/s and speed of separation = 4 m/s Therefore $e = \frac{4}{6} = \frac{2}{3}$

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A small sphere of mass 1kg is moving with a velocity (6^i+^j) ms−1 . It hits a fixed smooth wall and rebound with velocity (4^i+^j) ms−1 . The coefficient of restitution between the sphere and the wall is.

The correct option is A 2/3Impulse = Change in momentum 1(4^i+^j)−1(6^i+^j)=−2^iWhich is perpendicular to the wall.Component of initial velocity along ^i=6^i⇒ Speed of approach = 6 m/s and speed of separation = 4 m/s Therefore e=46=23

A small sphere of mass 1kg is moving with a velocity $(6^i +^j) {ms}^{- 1}$ . It hits a fixed smooth wall and rebound with velocity $(4^i +^j) {ms}^{- 1}$ . The coefficient of restitution between the sphere and the wall is.

The correct option is A 2/3
Impulse = Change in momentum $1 (4^i +^j) - 1 (6 {^i}_{+}^j) = - 2^i$

Which is perpendicular to the wall.

Component of initial velocity along $^i = 6^i$

$\Rightarrow$ Speed of approach = 6 m/s and speed of separation = 4 m/s Therefore $e = \frac{4}{6} = \frac{2}{3}$