A small sphere of mass $M$ is dropped from a great height, after it has fallen $100$ m, it has attained its terminal velocity and continues to fall at that speed. The work done by air friction against the sphere during the first $100$ m of fall is (g = acceleration due to gravity)

greater than the work done by air friction in the second 100 m

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less than the work done by air friction in the second 100 m

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equal to 100 Mg

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greater than 100 Mg

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Solution

The correct option is B less than the work done by air friction in the second 100 m
The air friction i.e. the viscous force is lower in the first half, because viscous force being proportional to velocity attains a maximum value at the terminal velocity. As the force is lower in the first 100 m the work done would also be lower compared to the next 100 m.

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A small sphere of mass M is dropped from a great height, after it has fallen 100 m, it has attained its terminal velocity and continues to fall at that speed. The work done by air friction against the sphere during the first 100 m of fall is (g = acceleration due to gravity)

A small sphere of mass $M$ is dropped from a great height, after it has fallen $100$ m, it has attained its terminal velocity and continues to fall at that speed. The work done by air friction against the sphere during the first $100$ m of fall is (g = acceleration due to gravity)