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Question

A small square loop of wire of side l is placed inside a large square loop of wire of side L (L > l). The loop are coplanar and their centre coincide. The mutual inductance of the system is proportional to

A
l/L
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B
l2/L
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C
L/l
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D
L2/l
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Solution

The correct option is B l2/L
Magnetic field produced due to large loop B=μ04π82iL
Flux linked with smaller loop
ϕ=B(l2)=μ04π8πil2L
ϕ=Mi M=πi=μ04π.82l2LMl2L

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