A small steam whistle (perfectly insulated and doing no shaft work) causes a drop of 0.8 kJ/kg in emthalpy of steam from entry to exit. If the kinetic energy of the steam at entry is negligible, the velocity of the steam at exit is
A
4 m/s
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B
40 m/s
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C
80 m/s
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D
120 m/s
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Solution
The correct option is B 40 m/s (b) Given data: Δh=−0.8kJ/kg h2−h1=−0.8kJ/kg h1−h2=0.8kJ/kg
Applying steady flow energy equation, h1+V212+gz1+q=h2+V212+gz2+w
Assumption:
(i) q=0 adiabatic flow
(ii) w=0
(iii) Change K.E. and P.E are neglect
(iv) Neglect inlet velocity. ∴h1=h2+V222 h1=h2+V222000 h1−h2=V222000
or 8=V222000 V22=1600orV2=40m/s