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Question

A small steel ball falls through a syrup at a constant speed of 10cms1. If the steel ball is pulled upwards with a force equal to twice its effective weight, neglecting buoyant force, how fast will it move upwards?

A
10cms1
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B
20cms1
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C
5cms1
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D
zerocms1
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Solution

The correct option is A 10cms1
As the ball falls under it's own weight with a constant speed, the syrup is able to generate enough drag to balance the ball's weight and restrict the ball at 10cm/s
Hence, when the ball is pulled upwards with twice the weight, it's weight gets cancelled out and the remaining weight-worth of force is cancelled out by drag of syrup equivalent to velocity of 10cm/s

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