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Question

A small straight conductor PQ is lying at right angles to an infinite current carrying conductor XY. If the conductor PQ is displaced on metallic rails of negligible resistance parallel to the conductor XY then


A
Q will be at higher potential and P will be at lower potential.
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B
P will be at higher potential and Q will be at lower potential.
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C
Both P and Q will be at the same potential.
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D
No emf will be induced.
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Solution

The correct option is B P will be at higher potential and Q will be at lower potential.
As per the faraday's Law of electromagnetic induction, an emf is induced in a moving conductor is,

E=l.(v×B)


We can see that the direction of the magnetic field is inward.

Here, B, l and v are mutually perpendicular.

E=Blv

Induced positive polarity is towards (v×B)

P has +ve polarity & Q has ve polarity.

Hence, option (B) is correct.

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