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Standard XII

Physics

Single Slit Diffraction

A small teles...

Question

A small telescope has an objective lens of focal length 144 cm and an eye piece of focal length 6.0 cm. What is the separation between the objective and the eye piece then?

0.75 m

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1.38 m

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1.0 m

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1.5 m

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Solution

The correct option is D 1.5 m
The seperation between the objective and the eye piece = Length of the telescope tube $f = f_{0} + f_{e}$
Here, $f_{0} = 144 c m = 1.44 m, f_{e} = 6.0 c m = 0.06 m$
$∴ f = 1.44 + 0.06 = 1.5 m$

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A small telescope has an objective lens of focal length 144 cm and an eye piece of focal length 6.0 cm. What is the separation between the objective and the eye piece then?

The correct option is D 1.5 mThe seperation between the objective and the eye piece = Length of the telescope tube f=f0+fe Here, f0=144cm=1.44m,fe=6.0cm=0.06m∴f=1.44+0.06=1.5m

The correct option is D 1.5 m
The seperation between the objective and the eye piece = Length of the telescope tube $f = f_{0} + f_{e}$
Here, $f_{0} = 144 c m = 1.44 m, f_{e} = 6.0 c m = 0.06 m$
$∴ f = 1.44 + 0.06 = 1.5 m$