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Question

A smooth block of mass 10 kg is released from rest from a height 5 m. It slides and compresses the spring of stiffness as shown in figure 200 Nm. The maximum compression of the spring is


A
25 m
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B
5 m
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C
2.5 m
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D
0
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Solution

The correct option is B 5 m
Using law of conservation of energy.
Δ K=Δ U
Since, block starts from rest and the block will come to rest at the time of maximum Compression Δ K=0.
Δ U=0
Taking spring and block as one system
Δ U=(Δ U)spring+(Δ U)gravity=0.
(Δ U)spring=(Δ U)gravity
12kx20=(0mgh)12kx2=mgh
Then x=2mghk=2×10×10×5200=5 m

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