A smooth sphere A of mass 0.1kg is moving with speed 5m/s when it collides head on with another smooth stationary sphere of same radius. If A is brought to rest by the impact and e=12, then,
A
speed of B just after impact is 2.5m/s
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B
the mass of B is 0.2kg
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C
magnitude of impulse during collision is 0.5Ns
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D
the mass of B is 0.4kg
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Solution
The correct options are A speed of B just after impact is 2.5m/s B the mass of B is 0.2kg D magnitude of impulse during collision is 0.5Ns At first B was at rest and finally A was at rest an e is given as 0.5 so vel. of B after collision = 1/2(vel. of A initially) =2.5m/s momentum will be conserved ,so 5∗0.1=2.5∗mm=0.2Kg impulse=5∗0.1−5∗0=0.5Ns