You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XIII

Physics

Perfectly Elastic Collision

A smooth sphe...

Question

A smooth sphere of mass 'M' moving with velocity 'u' directly collides elastically with another sphere of mass 'm' at rest. After collision their final velocities are 'V' and 'v' respectively. The value of 'v' is

$\frac{2 u M}{m}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{2 u m}{M}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{2 u}{1 + \frac{m}{M}}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$\frac{2 u}{1 + \frac{M}{m}}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$\frac{2 u}{1 + \frac{m}{M}}$

$v_{2} = (\frac{m_{2} - m_{1}}{m_{1} + m_{2}}) u_{2} + \frac{2 m_{1} u_{1}}{m_{1} + m_{2}} = \frac{2 M u}{M + m} = \frac{2 u}{1 + \frac{m}{M}}$

Suggest Corrections

Similar questions

A smooth sphere of mass 'M' moving with velocity 'u' directly collides elastically with another sphere of mass 'm' at rest. After collision their final velocities are 'V' and 'v' respectively. The value of 'v' is

Q. A smooth sphere of mass

M

moving with velocity

u

directly collides elastically with another sphere of mass

m

at rest. After collision, their final velocities are

V

and

v

respectively. The value of

v

is :

Q. A smooth sphere of mass

M

moving with velocity

u

directly collides elastically with another sphere of mass

m

at rest. After the collision, their final velocities are

V

and

v

respectively. The value of

v

is:

Q. A smooth sphere A is moving on a frictionless horizontal plane with angular speed

ω

and centre of mass velocity v. It collides elastically and head on with an identical sphere B at rest. Neglect friction everyone. After the collision, their angular speeds are

ω_{A}

and

ω_{B}

, respectively. Then

A smooth sphere A is moving on a frictionless horizontal plane with angular speed $ω$ and centre of mass is moving translationally with velocity 'v'. It collides elastically and head-on with an identical sphere B which is at rest. All surfaces are frictionless. After the collision, their angular speeds are $ω_{A}$ and $ω_{B}$ , respectively. Then,

Join BYJU'S Learning Program

A smooth sphere of mass 'M' moving with velocity 'u' directly collides elastically with another sphere of mass 'm' at rest. After collision their final velocities are 'V' and 'v' respectively. The value of 'v' is

The correct option is C 2u1+mM v2=(m2−m1m1+m2)u2+2m1u1m1+m2=2MuM+m=2u1+mM

The correct option is C
$\frac{2 u}{1 + \frac{m}{M}}$

$v_{2} = (\frac{m_{2} - m_{1}}{m_{1} + m_{2}}) u_{2} + \frac{2 m_{1} u_{1}}{m_{1} + m_{2}} = \frac{2 M u}{M + m} = \frac{2 u}{1 + \frac{m}{M}}$