Question

A smooth uniform rod of length $L$ and mass $M$ has two identical beads (1 and 2) of negligible size, each of mass $m$, which can slide freely along the rod. Initially the two beads are at the centre of the rod and the system is rotating with angular velocity ${\omega }_0$ about an axis perpendicular to the rod and is passing through its midpoint. There are no external forces when the beads reach the ends of the rod, the angular velocity of the system is :

• A. $\frac{M{\omega }_0}{M+6m}$
• B. $\frac{M{\omega }_0}{m}$
• C. $\frac{M{\omega }_0}{M+12m}$
• D. ${\omega }_0$

Answer 1

The correct option is A $\frac{M{\omega }_0}{M+6m}$

From conservation of angular momentum,

$\frac{M{L}^2}{12}{\omega }_0=[\frac{M{L}^2}{12}+2m{\left(\frac{L}{2}\right)}^2]\omega ,$

$\omega =\left(\frac{M}{M+6m}\right){\omega }_0$