CameraIcon

SearchIcon

MyQuestionIcon

692

You visited us 692 times! Enjoying our articles? Unlock Full Access!

Surface Tension

A soap bubble...

Question

A soap bubble having radius $\frac{1}{\sqrt{π}}$ cm is expanded to a bubble of radius $\frac{2}{\sqrt{π}}$ cm. If the surface tension of soap solution is 30 dynes/cm, the work done is:

A

180 erg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

360 erg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

720 erg

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

960 erg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 720 erg
Work done in blowing a soap bubble $W = 2 T (A_{2} - A_{1})$

So $W = 2 T (4 π r_{2}^{2} - 4 π r_{1}^{2}) = 8 π T (\frac{2^{2}}{π} - \frac{1}{π}) = 720 e r g$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Calculate the work done in increasing the radius of a soap bubble in air from

1 c m

2 c m

. The surface tension of soap solution is

30 d y n e / c m

π = 3.142

)

Q. A soap bubble of radius 12 cm is blown. Surface tension of soap solution is 30 dyne/cm. Calculate the work done in blowing the bubble.

Q. Calculate the work done in blowing a soap bubble from a radius of

2 c m

3 c m

. The surface tension of the soap solution is

30 d y n e c m^{- 1}

Q. The work done in forming a soap bubble of radius 10 cm from soap water of surface tension 35 dyne

c m^{- 1}

The radius of a soap bubble is increased from $\frac{1}{\sqrt{π}}$ cm to $\frac{2}{\sqrt{π}}$ cm If the surface tension of water is 30 dynes per cm, then the work done will be

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Surface Tension of Water

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Surface Tension

Standard VIII Chemistry

Join BYJU'S Learning Program

CrossIcon