A soap bubble in vacuum has a radius of 3 cm and another soap bubble in vacuum has a radius of 4 cm. If the two bubbles coalesce under isothermal condition, then the radius of the new bubble is

2.3cm

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4.5cm

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5cm

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7cm

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Solution

The correct option is C
5cm

$r = \sqrt{r_{1}^{2} + r_{2}^{2}} = \sqrt{9 + 16} = 5$ cm

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A soap bubble in vacuum has a radius of 3 cm and another soap bubble in vacuum has a radius of 4 cm. If the two bubbles coalesce under isothermal condition, then the radius of the new bubble is

The correct option is C 5cm r=√r21+r22=√9+16=5 cm

The correct option is C
5cm

$r = \sqrt{r_{1}^{2} + r_{2}^{2}} = \sqrt{9 + 16} = 5$ cm