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Question

# A soap bubble of radius 1.0cm is formed inside another soap bubble of radius 2.0cm. The radius of an another soap bubble which has the same pressure difference as that between the inside of the smaller and outside of large soap bubble, in meters is

A
6.67×103
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B
3.34×103
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C
2.23×103
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D
4.5×103
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Solution

## The correct option is B 6.67×10−3Given : a=1 cm b=2 cmLet surface tension of soap be T.For bubble of radius a :P2−P3=4Ta .....(1)For bubble of radius b :P1−P2=4Tb .....(2)Adding (1) and (2), we get P1−P3=4Ta+4Tb∴ 4TR=4Ta+4TbOr 1R=1a+1b∴ 1R=12+11We get R=23 cm=6.67×10−3 m

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