A soap bubble of radius r is blown up to form a bubble of radius 2r under isothermal conditions. If σ is the surface tension of soap solution, the energy spent in doing so is
24πσr2
Surface area of bubble of radius r=4πr2
Surface area of bubble of radius 2r=4π(2r)2=16πr2
Therefore, increase in surface area =16πr2−4πr2=12πr2
Since a bubble has two surfaces, the total increase in surface area =24πr2
∴ Energy spent = work done =24πσr2
Hence, the correct choice is (d).