Question

$A+SOC{l}_2\to B+S{O}_2+HCl$

$A+Na\to C+H_2$

$B+C\to (C_2{H}_5{)}_{2}O+NaCl$

The compound $A$ is:

• A. $C_2{H}_{5}Cl$
• B. $C_2{H}_{5}ONa$
• C. $C_2{H}_{5}OH$
• D. $C{H}_{3}OH$

Answer 1

The correct option is C $C_2{H}_{5}OH$

First alkyl halide form from alcohol, which then reacts with sodium ethoxide and ether forms as product.

Reaction of process:

$C_2{H}_{5}OH+SOC{l}_2\to C_2{H}_{5}Cl+S{O}_2+HCl$

(A) (B)

$C_2{H}_{5}OH+Na\to C_2{H}_{5}ONa+\frac{1}{2}{H}_2\uparrow$

(A) (C)

$C_2{H}_{5}Cl+C_2{H}_{5}ONa\to C_2{H}_5-O-C_2{H}_5+NaCl$

(B) (C)

Last step is Williamson's ether synthesis.

Option C is correct.