Question

A soft drink is available in two packs: (i) a tin can with a rectangular base of length 5 cm, breadth 4 cm and height 15 cm, and (ii) a plastic cylinder with circular base of diameter 7 cm and height 10 cm. Which container has greater capacity and by how much?

Answer 1

(i) Length of tin can, l = 5 cm

Breadth of tin can, b = 4 cm

Height of tin can, h = 15 cm

∴ Volume of soft drink in tin can = l × b × h = 5 × 4 × 15 = 300 cm³

(ii) Radius of plastic cylinder, r = $\frac{7}{2}$ cm

Height of plastic cylinder, h = 10 cm

∴ Volume of soft drink in plastic cylinder = $\mathrm{\pi }{r}^{2}h=\frac{22}{7}\times {\left(\frac{7}{2}\right)}^2\times 10$ = 385 cm³

So, the capacity of the plastic cylinder pack is greater than the capacity of the tin can pack.

Difference in the capacities of the two packs = 385 − 300 = 85 cm³

Thus, the capacity of the plastic cylinder pack is 85 cm³ more than the capacity of the tin can pack.