Question

A softball has a volume of about 29 cubic inches .

Find the radius of the softball.

Round your answer to the nearest tenth.

Answer 1

Step 1:

$V=\frac{4}{3}{\mathrm{\pi r}}^3$

Step 2:

$\begin{array}{rcl}29& =& \frac{4}{3}\mathrm{\pi }{\left(\mathrm{r}\right)}^3\\ \frac{3}{4\mathrm{\pi }}\times 29& =& {\mathrm{r}}^3\\ 6.9232& =& {\mathrm{r}}^3\end{array}$

Step 3:

$$\begin{gathered} \sqrt[3]{6.9232}=\sqrt[3]{{\mathrm{r}}^3}(\mathrm{Taking}\mathrm{cube}\mathrm{on}\mathrm{both}\mathrm{sides}) \\ 1.90=\mathrm{r} \end{gathered}$$

Final Answer: The radius of softball is about 1.90 in