Question

A soil deposit has a void ratio of 1.0. if the void ratio is reduced to 0.60 by compaction, the percentage volume loss is

• A. 10%
• B. 20%
• C. 30%
• D. 40%

Answer 1

The correct option is B 20%

Volume of soil $\left(V_s\right)$ remains constant

$V_s=\frac{V}{1+e}=Constant$

$\therefore \frac{V_1}{1+e_1}=\frac{V_2}{1+e_2}$

$\frac{V_1}{1+1}=\frac{V_2}{1+0.6}$

$\frac{V_2}{V_1}=\frac{1.6}{2}=\frac{4}{5}$

% volume loss

$=\left(\frac{V_1-V_2}{V_1}\right)\times 100\%=(1-\frac{V_2}{V_1})\times 100$

$=(1-\frac{4}{5})\times 100=20\%$