Question

A soil sample in its natural state has mass of 2.290 kg and a volume of 1.15 $\times$ ${10}^{-3}$$m^3$. After being oven dried, the mass of the sample is 2.035 kg. $G_s$ for soil is 2.68. The void ratio of the natural soil is

• A. 0.40
• B. 0.45
• C. 0.55
• D. 0.53

Answer 1

The correct option is D 0.53

Method -I:

$W_s=2.035kg,V=1.15\times {10}^{-3}{m}^3$

$V_s=\frac{2.035}{2.68\times {10}^3}=0.759\times {10}^{-3}{m}^3$

$e=\frac{V_v}{V_s}=\frac{V-V_s}{V_s}=\frac{1.15-0.759}{0.759}=0.515$

Method -II:

$Bulkdensityofsoil.$

$\gamma =\frac{Totalweight}{Totalvolume}$

$=\frac{2.29}{1.15\times {10}^{-3}}$

$=1.99\times$ ${10}^{3}kg/m^3$

$Watercontent,w=\frac{Weightofwater}{Weightofsolid}$

$=\frac{2.29-2.035}{2.035}$

$=0.125$

We know that,

$\gamma =\frac{G(1+w){\gamma }_w}{1+e}$

$1.99\times {10}^3=\frac{2.68(1+0.125)\times 1000}{1+e}$

$e=0.515$

Hence the corrent option is (d).