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Question

A solar energy bases heat engine which receives $80$ kJ of heat at $100^{o} C$ and rejects $70$ kJ of heat to the ambient of $30^{o} C$ is to be designed. The thermal efficiency of the heat engine is

A

18.8

%

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B

Indetermine

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C

70

%

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D

12.5

%

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Solution

The correct option is D $12.5$ %

Given data: $Q_{1} = 80 k J$
$T_{1} = 100^{o} C = 373 K$
$Q_{2} = 70 k J$
$T_{2} = 30^{o} C = (30 + 273) K = 303 K$
Thermal efficiency,
$η = \frac{W}{Q_{1}} = \frac{Q_{1} - Q_{2}}{Q_{1}} = \frac{80 - 70}{80}$
$0.125 = 12.5$ %

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