A solenoid has a core of a material with relative permeability $400$ . The windings of the solenoid are insulated from the core and carry a current of $2 A$ .If the number of turns is $1000$ per meter, calculate (a) $H$ , (b) $B$ and (c) the magnetising current $I_{m}$ .

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Solution

Given : $μ_{r} = 400$ $i = 2 A$ $n = 1000$ turns per meter
(a) $H = n i = 1000 \times 2 = 2000 A / m$
(b) $B = μ_{o} H = 4 π \times 10^{- 7} \times 2000 = 8 π \times 10^{- 4} T$
(c) $I_{m} = χ H = 399 \times 8 π \times 10^{- 4} = 10 A / m$

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A solenoid has a core of a material with relative permeability 400. The windings of the solenoid are insulated from the core and carry a current of 2A.If the number of turns is 1000 per meter, calculate (a) H, (b) B and (c) the magnetising current Im.

Given : μr=400 i=2A n=1000 turns per meter(a) H=ni=1000×2=2000A/m(b) B=μoH=4π×10−7×2000=8π×10−4 T(c) Im=χH=399×8π×10−4=10 A/m

A solenoid has a core of a material with relative permeability $400$ . The windings of the solenoid are insulated from the core and carry a current of $2 A$ .If the number of turns is $1000$ per meter, calculate (a) $H$ , (b) $B$ and (c) the magnetising current $I_{m}$ .

Given : $μ_{r} = 400$ $i = 2 A$ $n = 1000$ turns per meter
(a) $H = n i = 1000 \times 2 = 2000 A / m$
(b) $B = μ_{o} H = 4 π \times 10^{- 7} \times 2000 = 8 π \times 10^{- 4} T$
(c) $I_{m} = χ H = 399 \times 8 π \times 10^{- 4} = 10 A / m$