Question

A solenoid has a core of a material with relative permeability of 500. The windings of the solenoid are insulted from the core and carry a current of 2A. If the number of turns is 1000 per meter, then magnetisation is ??

Answer 1

We know B=μrμ0H

M=(B-μ0H)/μ0

Using Value of B from above

M= (μrμ0H-μ0H)/μ0
M= ((μr-1)μ0H)/μ0 ( taking μ0H common)

Cancelling μ0

M = (μr-1)H
Given μr= 500
Hence M = (500-1)* 2000
M= 499*2000
= 998000 A/m