Question

A solenoid of length $1.0m$, radius $1cm$ and total turns $1000$ wound on it, carries a current of $5A$. Calculate the magnitude of the axial magnetic field inside the solenoid. If an element was to move with a speed of $104m/s$ along the axis of this current carrying solenoid, what would be the force experienced by this electron?

Answer 1

$B={\mu }_{0}ni$ $=$ ${\mu }_0\frac{n}{l}i$

$=$ $\left(4\pi \times {10}^{-7}\right)\frac{1000}{1}\times 5$

$B=2\pi \times {10}^{-3}$

force on the electron$=$ $qVB$

$=$ $\left(1.6\times {10}^{-19}\right)\times 104\times 2\pi \times {10}^{-3}N$

$Fe=1.044\times {10}^{-19}N$

Hence the force experienced by this electron is $Fe=1.044\times {10}^{-19}N$