Question

A solenoid of length $1m$ and $0.05m$ diameter has $500$ turns. If a current of $2A$ passes through the coil, calculate the co-efficient of self induction of the coil.

Answer 1

Self-inductance$=L=\frac{{\mu }_0{N}^{2}A}{l}$
$=\frac{4\pi \times {10}^{-7}\times 500\times 500\times 3.14{\left(0.025\right)}^2}{1}$
$=0.616\times {10}^{-3}H$