A solid A⁺B^- has the B^- ions arranged as below. If the A⁺ ions accupy half of the tetrahedral sites in the structure. The formula of solid is:

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AB₂

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A₂B

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A₃B₄

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Solution

The correct option is A AB
In a closed packed structure, the number of tetrahedral voids per atom of the crystal is two. Since, half of the tetrahedral voids are occupied by A⁺, the number of A⁺ is same as that of B^- in the crystal. Thus, formula is AB. Or

No. of B^- ions in until cell =

A⁺ ions occupies 50 of tetrahedral voids =
The ratio of B^- and A⁺ is 1:1

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Similar questions

A solid A⁺B^- has the B^- ions arranged as below. If the A⁺ ions accupy half of the tetrahedral sites in the structure. The formula of solid is:

A^{+} B^{-}

B^{-}

A^{+}

B^{-} i o n s

A^{+} i o n s

(A^{+} B^{-})

B^{-}

A^{+}

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