Question

A solid brass sphere of volume 0.305 $m^3$ is dropped in ocean, where water pressure is $2\times {10}^{7}N/m^2$. The bulk modulus of water is $6.1\times {10}^{10}N/m^2$. What is the change in volume of sphere?

Answer 1

Given : $V=0.305m^3$ $P=2\times {10}^{7}N/m^2$ $B=6.1\times {10}^{10}N/m^2$

Bulk modulus $B=\frac{-P}{\Delta V/V}$

Or $6.1\times {10}^{10}=\frac{-2\times {10}^7}{\Delta V/\left(0.305\right)}$

$⟹\Delta V=-1\times {10}^{-4}{m}^3$