A solid circular shaft is subjected to a torque T(in Nm), which produces a maximum shear stress of fs(inN/mm2) in the shaft. The required diameter of the shaft would be
A
10(16Tπfs)1/3
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B
10(πfs16T)1/3
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C
10(16Tπfs)1/2
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D
10(πfs16T)1/2
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Solution
The correct option is A10(16Tπfs)1/3 fs=16πd3(T×103)