Question

A solid composed of a cylinder with hemispherical ends on both the sides.
The radius and height of the cylinder are 20 cm and 30 cm respectively. Find the total surface area of solid. (Take $\pi$ = 3.14)

Answer 1

Radius of the cylinder $=$ Radius of each hemisphere $=r=20$ cm
Height of cylinder, $h=35$ cm
$\therefore$ T.S.A. of the solid
$=$ C.S.A. of the cylinder $+$ 2 $\times$ C.S.A. of the hemisphere
$=2\pi rh+2\times 2\pi r^2$
$=2\pi r(h+2r)$
$=2\times 3.14\times 20(35+2\times 20)$
$=125.6\times 75$
$=9,420c{m}^2$
$\therefore$ Total surface area of the given solid is $9,420c{m}^2$