A solid cone of height 8 cm and base radius 6 cm is melted and recast into identical cones,each of height 2 cm and diameter 1 cm.Find the number of cones formed.

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Solution

No of cones
= $\frac{v o l u m e o f b i g c o n e}{v o l u m e o f s m a l l c o n e}$
= $\frac{π R^{2} H}{π r^{2} h}$
= $\frac{(6^{2} \times 8)}{({0.5}^{2} \times 2)}$
=576 cones

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A solid cone of height 8 cm and base radius 6 cm is melted and recast into identical cones,each of height 2 cm and diameter 1 cm.Find the number of cones formed.

No of cones = volume of big conevolume of small cone =πR2Hπr2h =(62 × 8)(0.52 × 2) =576 cones

No of cones
= $\frac{v o l u m e o f b i g c o n e}{v o l u m e o f s m a l l c o n e}$
= $\frac{π R^{2} H}{π r^{2} h}$
= $\frac{(6^{2} \times 8)}{({0.5}^{2} \times 2)}$
=576 cones