A solid cube and a solid sphere of the same material have equal surface area. Both are at the same temperature and enclosed in the same surroungings. Then
The cube cools down faster than the sphere
Rate of cooling of a body
R=△θt=Aϵσ()T4−T40mc
⇒R∝Am∝AreaVolume
⇒ For the same surface area. R∝1Volume
∵ Volume of cube < volume of sphere
⇒RCube>RSphere i.e. cube, cools down with faster rate.