A solid cube of dimensions $50 c m \times 50 c m$ and weighing $25 N$ placed on a table. Calculate the pressure exerted on the table.

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Solution

The magnitude of the pressure $(P)$ exerted by an object on a given surface is equal to its weight $(F)$ acting in the direction perpendicular to that surface divided by the total surface area of contact $(A)$ between the object and the surface.
$P = \frac{F}{A} = \frac{F}{a^{2}}$
where $a$ is the dimension of the cube.
Given that $a = 50 c m = 0.5 m, F = 25 N$

$⟹ P = \frac{25}{0.5 \times 0.5}$

$⟹ P = 100 P a$

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A solid cube of dimensions 50 cm×50 cm and weighing 25 N placed on a table. Calculate the pressure exerted on the table.

A solid cube of dimensions $50 c m \times 50 c m$ and weighing $25 N$ placed on a table. Calculate the pressure exerted on the table.