A solid cube of mass 5kg is placed on a rough horizontal surface, in xy−plane as shown. The friction coefficient between the surface and the cube is 0.4. An external force →F=6^i+8^j+20^kN is applied on the cube.(use g=10m/s2 )
A
The block starts slipping over the surface
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B
The friction force on the cube by the surface is 10N
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C
The friction force acts in xy−plane at angle 1270 with the positive x− axis in clockwise direction
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D
The contact force exeerted by the surface on the cube is 10√10N
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Solution
The correct option is A The block starts slipping over the surface Given, external force →F=6^i+8^j+20^kN F=√62+82+202=√500=22.36N and Fs=μN Fs=0.4×5×10=20N Since Fs<F, the cube will slide.