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Question

# A solid cube of mass 5 kg is placed on a rough horizontal surface, in xy−plane as shown. The friction coefficient between the surface and the cube is 0.4. An external force →F=6^i+8^j+20^k N is applied on the cube.(use g=10 m/s2 )

A
The block starts slipping over the surface
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B
The friction force on the cube by the surface is 10 N
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C
The friction force acts in xyplane at angle 1270 with the positive x axis in clockwise direction
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D
The contact force exeerted by the surface on the cube is 1010 N
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Solution

## The correct option is A The block starts slipping over the surfaceGiven, external force →F=6^i+8^j+20^k N F=√62+82+202=√500=22.36 N and Fs=μN Fs=0.4×5×10=20 N Since Fs<F, the cube will slide.

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