Question

A solid cylinder has mass '$M$', radius '$R$' and length '$l$'. Its moment of inertia about an axis passing through its center and perpendicular to its own axis is

• A. $\frac{2M{R}^2}{3}+\frac{M{l}^2}{12}$
• B. $\frac{M{R}^2}{3}+\frac{M{l}^2}{12}$
• C. $\frac{3M{R}^2}{4}+\frac{M{l}^2}{12}$
• D. $\frac{M{R}^2}{4}+\frac{M{l}^2}{12}$

Answer 1

The correct option is D $\frac{M{R}^2}{4}+\frac{M{l}^2}{12}$

$I_2=I_x+I_y\frac{1}{12}m{l}^2+\frac{1}{4}m{R}^2$