Question

A solid cylinder of mass 10 kg is rolling perfectly on a plane of inclination ${30}^o$. The force of friction between the cylinder and the surface of the inclined lane is

• A. 49N
• B. 24.5N
• C. 49/3N
• D. 12.25N

Answer 1

Answer: (A)

49N

Given,

$m=10kg$

$g=9.8m/s^2$

$\theta ={30}^0$

From free body diagram,

contact force,

$N=mgcos\theta$. . . . . .(1)

Frictional force between the cylinder and the surface of the inclined lane is given by,

$f_{\mu }=mgsin\theta$. . . . . .(2)

$f_{\mu }=10\times 9.8\times sin{30}^0$

$f_{\mu }=49N$

The correct option is A.