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Question

A solid cylinder of mass 20 kg rotates about its axis with an angular speed of 100 rad/s. The radius of the cylinder is 0.25 m. The kinetic energy associated with the rotation of the cylinder is

A
3125 J
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B
725 J
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C
31.25 J
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D
7.25 J
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Solution

The correct option is A 3125 J
Given, M=20 kg
ω=100 rad/s
R=0.25 m
Moment of inertia of the solid cylinder about its axis of symmetry
I=12MR2=12×20×(0.25)2
=10×0.0625=0.625 kg m2
Kinetic energy associated with the rotation of the cylinder is given by
KE=12Iω2
=12×0.625×(100)2
=0.3125×10000
=3125 J

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