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Question

A solid cylinder of mass 20kg rotate about it's axis with angular speed of 100 rad/s the radius of the cylinder is 0.25 m the kinetic energy associated with the rotation of the cylinder is

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Solution

Mass of the cylinder, m = 20 kg
Angular speed, ω = 100 rad s–1
Radius of the cylinder, r = 0.25 m
The moment of inertia of the solid cylinder:
I = mr2 / 2
= (1/2) × 20 × (0.25)2
= 0.625 kg m2
∴ Kinetic energy = (1/2) I ω2
= (1/2) × 6.25 × (100)2 = 3125 J

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