A solid cylinder of radius $r$ and a hollow cylinder with inner and outer radius $r$ and $2 r$ respectively of the same masses are placed on a horizontal table top.
If $P_{1}$ and $P_{2}$ are the pressure exerted due to solid and hollow cylinder respectively, then

P_{1} = 2 P_{2}

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P_{1} = 3 P_{2}

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P_{1} = P_{2}

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P_{2} = 2 P_{1}

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Solution

The correct option is C $P_{1} = P_{2}$

P= $\frac{f}{A}$
$where f = m g$
$A = A r e a$
$for Both f & A are Same.$
$Answer:- (C) P_{1} = P_{2}$

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A solid cylinder of radius r and a hollow cylinder with inner and outer radius r and 2r respectively of the same masses are placed on a horizontal table top.If P1 and P2 are the pressure exerted due to solid and hollow cylinder respectively, then

The correct option is C P1=P2P=fA where f=mgA=Area for Both f&A are Same. Answer:- (C) P1=P2

A solid cylinder of radius $r$ and a hollow cylinder with inner and outer radius $r$ and $2 r$ respectively of the same masses are placed on a horizontal table top.
If $P_{1}$ and $P_{2}$ are the pressure exerted due to solid and hollow cylinder respectively, then

The correct option is C $P_{1} = P_{2}$

P= $\frac{f}{A}$
$where f = m g$
$A = A r e a$
$for Both f & A are Same.$
$Answer:- (C) P_{1} = P_{2}$