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Question

A solid cylindrical conductor of radius R has a uniform current density. The magnetic field H insider the conductor at a distance r from the axis of the conductor is:

A
I/2πr
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B
I/4πr
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C
Ir/2πR2
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D
Ir/4πR2
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Solution

The correct option is C Ir/2πR2

Magnetic field at a distance r inside a conductor of radius R is given by ampere’s circuital law

B×2πr=μ0Jπr2

B=μ0Jr2

B=μ0rI2πR2

Thus magnetic field inside a conductor is given by

B=μ0rI2πR2

Magnetic field strength

H=Bμ0

H=Ir2πR2


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